D ratio U supplied represents an everyday purchase ratio, Assuming today to be Tuesday, so we have Tuesdays purchase to be
T-0.04
C-0.06
A-0.50
R-0.20
L-0.15
O-0.05
All in %, sums up to 100%
Given relationships are:
1. T(Monday)= 1.07R(Sunday) 7% more Remember We assumed Today to be Tuesday, thus yesterday will be Monday, the day before being Sunday
2. R(Sunday)= 0.97C(Tuesday) 3% less
3. C(Tuesday)= 5kg
Find:
I) A(Monday)
Substitute C(Tuesday)= 5kg into the 2nd relationship i.e R(Sunday)= 0.97C(Tuesday)
therefore
R(Sunday)= 0.97(5kg)
R(Sunday)= 4.85kg
Solve for T(Monday) by substituting R(Sunday)=4.85kg into the 1st Relationship i.e T(Monday)= 1.07R(Sunday)
thus
T(Monday)= 1.07(4.85kg)
T(Monday)= 5.1895kg
We now have at least one concrete value for the quantity of Tomatoes bought for Yesterday(Monday), we can now use the ratio of daily purchase to find the quantity of any other item bought yesterday, in this case the Apples
Recall that:
T- 0.04% (4/100)
A- 0.50% (50/100)
to get the total quantity (X) of items bought yesterday would be;
4X/100 = 5.1895kg
cross-multiplying;
4X = 518.95kg
Solving for X (Making it the subject of the formular by dividing both sides by 4)
X = 129.74kg
Apple is 50% of X, thus
A= 0.5(129.74)
A= 64.87kg
The above is the quantity of Apples bought by John yesterday.
I took time to illustrate it all, in a normal test condition most of these steps can be solved visually, and everything taken care of under a minute, best of luck bro, keep preparing, the day of reward is sure coming, and our God who sees in the secret will reward U in the open