Printable View
Age group under 35 - Average number of daily commuters is 425600 under age 35 this year.
Rail commuters 43%
Car 9%
Subway 27%
Bus 12 %
Others 9%
Question - If the number of bus passenger who are under 35 decreased by 0.8% next year , and 11% of this age group travelled by bus, approximately how many commuters would be under 35.
Solve and put your answer here... ;D
Men see people still dey solve when I just licked out one of the chevron shl question to come next month... ;D
Time don go oooo
Approximately 460580 passengers under d age group of 35 by next year. I hope i'm correct.
You got it..Can you briefly explain how you arrived at the answer..
Number of those who commuted by bus this year = 12 % of 425600= x
Number of those who would commute by bus next year = x- 0.8% of x = y
Number of those who would commute by bus next year = 11% of z = y
where z is the total number of commuters under 35, so find z.
Use your calculator, if you know x, then you know y, if you know y, then you know z
Quite easily done
According to data on age group below 35,
average no of daily commuters = 425600
commuters who use buses as a means of transportation = 12/100 * 425600 = 51072 (present yr)
a decrease in bus passenger by 0.8% next yr can be expressed mathematically as:
51072 - 0.008(51072) = 50663.4 (next year)
commuters who enter buses as a means of transportation next yr = 11% * t = 50663.4
where t is d average no of daily commuters next yr.
Hence, p = 50663.4/0.11 = 460580 approximately.
@Yemmi-- It would have been nice if you can outline it with figures because from what you explained here. You seems to be wrong except am missing something out.
From you explaination
Number of those who commuted by bus this year = 12 % of 425600= x -- where x = 51,072
Number of those who would commute by bus next year = x- 0.8% of x = y -- where x which is 51072 - 0.8% of x which is = 408.6 in subraction detailed... 51072 - 408.6= y where Y would be = 50663.4
Number of those who would commute by bus next year = 11% of z = y -- 11% of 425600 = 46816 = Y like you said. Now we have two values for Y, they 408.6 and 46816, --- Blunder in representation..Or what happened here.
Further as you said If I know X? x = 51072
iF i know Y? y(1)= 408.6
if i know Y y (2)= 46816
if i know z? Z= 425600
Sorry you got it wrong or misplaced... Try and fine tune properly for others to understand.
:-[
@ adexzy007, can you post the complete questions for the benefit of those in the house that applied to Chevron.
@ pein....You are good..Nice one.. ::)
@God's Favour -- how can you believe a question licked from chevron.. Sorry that is just question number 5 of the shldirect online site...I froze it up and have been working on it lately....Pele....Work hard and don't wait for licks....lol......if anything show sha...i go here... ;D
This type of question is very easy and should be solved in a minute. If someone cant solve this they will most likely find it quite difficult to pass any mobil or chevron type numerical test as i have taken 2 mobil tests and seen questions from chevron. So please its not a matter of "solve this if you are good". I advise anyone having issues with such questions and is hoping to pass a premium oil company test should do a lot of practicing before the test date...
@Navy you can now talk. This has been here since but you didn't borther to talk oo..Now it;s been solve u are talking... ::)
lol@ adexzy. I'm just making a point. The question is a one minute question for me. i would have helped out if i saw it earlier. What im trying to say is u need to practice more so that u can be comfortable with such questions as these questions are quite familiar with shl for mobil and chevron, even harder ones. The more u practice the more comfortable you will become. Another word of advise when solving these questions try to be able to them in your head without calculators as one of the mobil tests i did calculators were not allowed. Strategy is round of the numbers as short as possible. ie take of decimals and estimate alot because the options the answers will most likely not be close(eg. a:10 b:200 c:500 d:900) so instead of trying to be pinpoint accurate just estimate and get answers closest to the answer option and choose that..Have a blessed day and may God bless your endeavours..
wise one.... ;D
Smart Engineers. Any other question to solve?
@ Adexy007, u are the one at fault and not Yemmi. he got it right. Where u went wrong was wen u found a second value for y. Why would u need a second value when u already have y and z is an unknown?
U just av to do substitution and u get 11% * z = 50663.4 (this is y). Then u cross multiply and u get (50663.4*100)/11 = 460580 approximately.
Easy as ABC.
That means you didnt see what he outlined. Go back to it so that you see where he got 2 values of y. I didnt make it up. ;D
You can say easy as ABC but yesterday I threw it here, you didnt say anything oo.. Na for hall you go know sey it's difficult as XYZ when your is hotting...lol
U didnt read it accurately. He found only one y. The second y he wrote was for you to substitute the value of y that had already been found.
I didnt respond earlier cos i just saw the post. I like such questions and always practice my shl type questions.
This is a very interesting thread. Adexy you have done a very good job, and all members who have responded. Please lets try and make some of this kind of thread.
op is olodo yemmi & pein don rescue u