Printable View
Ma broda, d alert is equaly v.important. Waitd al day.wetin dey hapen nw. Les i forget to expres my sincere thanx to all esp ctr07 for d perfect descriptn of cham city route 4rm ib. It was just as u said.one love people. Wish u al and myself God favour
alert! Alert!! Alert!!! Anybody with info on when dey will be paying pls. And how much are we expecting.
What do you mean by functional test?Quote:
Originally Posted by maestrob
What function are we refering to here Gradute trainee
Who else knows what to expect in the next stage?
Noticed the questions were note dragnet's
does any body know how much we wud be getting as transport reimbursement and when dey wud be paying the reimbursements? is it a fixed amount or like shell, it depends on location?
Hi guys.. pls since learning is a continuous process; can any1 remember the question on cats & mice - something like if a certain amount of cats catch equal no. of cats totalling 999199 (i think), if the no. of cats are less than mice. how many mice did each cat catch.. pls, not too sure of d details again, any1 that remembers & can solve it, should pls help out.. thanks ..
@bonethugs.
my brother dat cat and mice thing no funny at all. I look d tin sote, it made me feel like i be olodo. It looks simple but it's complex.
My bro, that is not necessary, we have done it and its in the past now. So lets just keep praying and be hopeful cos what we need is His Grace and not 10/10.Quote:
Originally Posted by bonethugs89
Goodluck!
learning is a continuous process like he said,so if u have an idea,pls post it
u neva can tell who will be needing it
A Cat can only catch one Mouse at a time, even if they(Mice) are rained down from the sky... I think the answer is one, except your question is incomplete.
@bonethugs89, there is 991 in the options?
@ justice59, yea i think there's was 991 & 691.. i randomly picked 691 since it was the least among the options ....
No. of cats = x(say)
Therefore, no. of mice killed by each cat = 999919/x (since, they killed equal no. of mice)
Now, given that
(999919/x) is greater than x, i.e
999919/x > x, implies x*x<999919
Therefore, x < 999.95(approx). Now, the only no. which is nearest to but less than 999.95 and is a factor of 999919 is 991.
Thus, x = 991 and no. of mice = 999919/991 = 1009.
Ans=991..
(From one site thru google search)
Here is anoda way to look at it-
Observing the num 999919 which is the total num of rats being eaten..we can write it as
(1000000-81) = (1000^2-9^2) = (1000+9)(1000-9) = (1009)(991)
so total num of rats killed =(1009)(991)
and given that each cat kills more num of rats than the total num of cats
hence each cat kills 1009 num of rats
and there are 991 num of cats.
(No be me solve am oh.. )